Is Ross Lynch Still Dating Jaz Sinclair: As for if theyre still together, J-14

Ross Lynch and Jaz Sinclair are actors who co-starred together on the Netflix series “Chilling Adventures of Sabrina. Yes, Ross Lynch and Jaz Sinclair are still together.







Image Source: Jaz Sinclair Instagram. In a 2019 interview Entertainment Tonight, Ross declared that what he has with Jaz is merely a closely-knit friendship and nothing more. Recently Lynch and The Driver Era released a new single called ‘Rumors’. 25, 2020 Jacopo Raule/Getty Images Entertainment/Getty Images While I totally.















As of Oct.



Ross and Jaz have deliberately kept fans in the dark about the budding romance. American actor and singer Ross Lynch (known for Austin & Ally, Chilling Adventures of Sabrina) and American actress Jaz Sinclair (known for Chilling Adven.

Are Ross Lynch and Jaz Sinclair still together? Despite being a fan-favourite couple for over five years, fans of Ross Lynch and Jaz Sinclair's romance have begun to speculate that the couple have parted ways. Fabiana Beuses. ET's Katie Krause sat down with the 23-year-old actor and his brother, Rocky, on Tuesday, where Ross dished on rumors that he's dating his Sabrina co-star, Jaz Sinclair.



Ross Lynch Addressed Speculation That He and Chilling Adventures of Sabrina Star Jaz Sinclair Are Dating "What does Instagram official even mean?" By Lauren Rearick January 16, 2019.

Jaz Sinclair has been in relationships with Ross Lynch (2018 - 2022) and Justice Smith. Ross is currently dating his fellow actor, Jaz Sinclair from Paper Towns and The Vampire Diaries series.



As of October 2023, it appears that Ross Lynch and Jaz Sinclair are no longer together. As for if they're still together, J-14.

9 min of Ross lynch talking about his girlfriend Jaz Sinclair

Jaz and Ross met on the set of Chilling Adventures of Sabrina back in 2018. Ross Lynch is dating his girlfriend Jaz Sinclair in 2021.

I especially love them ….

Is Ross Lynch Dating Lily Urick After His Split From Jaz Sinclair?